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3.3x^2+2.3x-3.6=0
a = 3.3; b = 2.3; c = -3.6;
Δ = b2-4ac
Δ = 2.32-4·3.3·(-3.6)
Δ = 52.81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.3)-\sqrt{52.81}}{2*3.3}=\frac{-2.3-\sqrt{52.81}}{6.6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.3)+\sqrt{52.81}}{2*3.3}=\frac{-2.3+\sqrt{52.81}}{6.6} $
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